![]() ![]() How do I get a handle on that image in memory so that I can do cv2.imshow('image',img) and all kinds of cool stuff thereafter. However, from the errors that I encountered, I guess it is expecting a numpy array or a scalar as the first argument. ![]() The documentation doesn't really mention what the imdecode function returns. Img = cv2.imdecode(file_bytes, 0) #Here as well I get returned nothing inmemfile io.BytesIO() img.save(inmemfile, format 'PNG') reset file pointer to start ek(0) imgbytes inmemfile.read() base64encodedresultbytes base64.b64encode(imgbytes) base64encodedresultstr base64. You can achieve this without creating a temporary file by using an in memory file, with io.BytesIO(). Getting the bytes from decoded string and converting it into an numpy array of sorts file_bytes = numpy.asarray(bytearray(imgdata), dtype=numpy.uint8) You need to base64 encode before you can decode. I tried img = cv2.imdecode(npImage,0), this returns nothing. But the problem is: my API needs to be able to receive a base64 encoded image and return one of my categories from an array, like: categories 'dog', 'cat' not a number like the prediction variable API from the tutorial returns. I get cv not defined as I have openCV3 installed which is available to me as cv2 module. Using PIL reference: pilImage = Image.open(StringIO(imgdata)) I have tried two solutions that seem to be working for some people. I want to be able to read the image into the memory directly creating the img object. However I don't think so many File IO operations are feasible considering I'd be doing this for every frame of the stream. The above code snippet works and the image file gets generated properly. Imgdata = base64.b64decode(imgstring) #I use imgdata as this variable itself in references below print (picture.format) If the image is stored as hex in a plaintext file picturecode.dat similar to your Google Docs link, it needs to first be. So, I designed my client codeto encode the image into a base64 string and send it to the server, which received it succesfully. I found it effective to convert the byte of the image into base64 and transmit it. From this SO answer, if I do something like: import base64 If the image is stored as a binary file, open it directly: import PIL Create Image object picture ('picturecode.dat') display image picture.show () print whether JPEG, PNG, etc. I am trying to make a code for image style transfer based on FastAPI. I am expecting the output from the text document to be the same output that is inserted into my Mongo Database.The official doc says, that imread accepts a file path as the argument. close () Note: We will use the above-created string for converting it back to the image. Decode The Binary With b64.decode () Then Close The File With. Then Just Give Any Image File Name ( ex:myimage.png) And Open It In wb Mode W rite In B inary. # check if the file exists or not in our folderĬoll.insert_one() Store The Data That was Read From File Into A Variable. If file_name.lower().endswith(('.png', '.jpg', '.jpeg', '.tiff', '.bmp', '.gif')):īs64_str = base64.b64encode(image_file.read())Ĭonnection = pymongo.MongoClient(conn_str, serverSelectionTimeoutMS=5000)įile_name = input("Enter the image name to upload: ") ![]() The issue is that I am getting the output in the image below in my MongoDB Database. I added the line of code to output enc_file to a text document, and that is the correct Base64 which can then be converted back to an image. This issue is that whenever I try to put it into MongoDB it is giving me a different string. I am trying to take an image and upload that to my MongoDB as base64. Below is the Python code that am using to try to get this done.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |